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March 27, 2017

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According to the following reaction, how many grams of zinc hydroxide will be formed upon the complete reaction of 29.8 grams of water with excess zinc oxide?

ZnO (s) + H2O (l) Zn(OH)2 (aq)

  • chemistry - ,

    ZnO (s) + H2O (l) ---> Zn(OH)2 (aq)

    same number of moles of Zn(OH)2 as of water

    water = 2 + 16 = 18 grams/mol
    so
    29.8/18 = 1.66 moles of H2O and of Zn(OH)2

    Zn = 65
    2O = 32
    2H = 2
    -------
    99 grams/mole
    99*1.66 = 154 grams Zn(oh)2

  • chemistry - ,

    the above is wrong, its 2*16 not 2+16

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