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February 1, 2015

February 1, 2015

Posted by **John** on Saturday, March 31, 2012 at 8:27pm.

a = 39, c = 40, angle A = 36°

angle B1 = ° angle B2 = °

angle C1 = ° angle C2 = °

b1 = b2 =

- Pre-Calc Helppp!!! -
**Damon**, Saturday, March 31, 2012 at 8:44pmsin 36/39 = sin C /40

C = sin^-1(40/39)sin 36 = 37

B = 180 - A -C = 107

C could also be in Quadrant 2

180 - 37 = 143

then B is 180 - 36 -143 = 1 deg

sinB/b = sin 36/39 = .0151

so

b = sin B/.0151

b1 = sin 1 /.0151 = 1.16

b2 = sin 107/.0151 = 63.3

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