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Posted by on Saturday, March 31, 2012 at 7:23pm.

Need help please:

(3,0) (7,6)
(x-7)2 + (y-6)2 = 7(2)
(x-7)2 + (y-6)2 = 49

Having difficulty with this problem.Can someone help?


geometry - Reiny, Saturday, March 31, 2012 at 8:07am
You don't say what the actual problem is.

I see the resemblance to finding the equation of a circle??

What are you trying to find?

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geometry - Kel, Saturday, March 31, 2012 at 6:59pm
It says to write an equation of a circle with diameter
__
AB

  • Geometry - , Saturday, March 31, 2012 at 7:31pm

    Is A at (3,0) and B at (7,6) ?
    if so then the center is halfway between.
    Xc = (3+7)/2 = 5
    Yc = (0+6)/3 = 3
    so of form
    (x - 5)^2 + (y - 3)^2 = r^2
    but r is half the length of AB
    AB^2 = 4^2 + 6^2 = 16+36 = 52
    AB = 7.21
    (1/2) AB = r = 3.61
    r^2 = 13
    so in the end
    (x - 5)^2 + (y - 3)^2 = 13

  • Geometry - , Saturday, March 31, 2012 at 7:42pm

    Thanks for your help!

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