Posted by **Kel** on Saturday, March 31, 2012 at 7:23pm.

Need help please:

(3,0) (7,6)

(x-7)2 + (y-6)2 = 7(2)

(x-7)2 + (y-6)2 = 49

Having difficulty with this problem.Can someone help?

geometry - Reiny, Saturday, March 31, 2012 at 8:07am

You don't say what the actual problem is.

I see the resemblance to finding the equation of a circle??

What are you trying to find?

****************

geometry - Kel, Saturday, March 31, 2012 at 6:59pm

It says to write an equation of a circle with diameter

__

AB

- Geometry -
**Damon**, Saturday, March 31, 2012 at 7:31pm
Is A at (3,0) and B at (7,6) ?

if so then the center is halfway between.

Xc = (3+7)/2 = 5

Yc = (0+6)/3 = 3

so of form

(x - 5)^2 + (y - 3)^2 = r^2

but r is half the length of AB

AB^2 = 4^2 + 6^2 = 16+36 = 52

AB = 7.21

(1/2) AB = r = 3.61

r^2 = 13

so in the end

(x - 5)^2 + (y - 3)^2 = 13

- Geometry -
**Kel**, Saturday, March 31, 2012 at 7:42pm
Thanks for your help!

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