Posted by Robert on Saturday, March 31, 2012 at 7:08pm.
H2SO4 + 2NH4OH -> (NH4)2SO4 + 2H2O
so, 1 mole of H2SO4 reacts with 2moles NH4OH
So, how many moles in 10ml of .5M H2SO4?
.01L * .5moles/L = .05 moles H2SO4
So, how many moles of NH4OH will be used?
I might point out here that it has been shown that NH4OH does not exist. It is convenient to write NH3(aq) + H2O ==> NH4OH ==> NH4^+ + OH^- but the intermediate is not there.
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