Posted by Anil on Saturday, March 31, 2012 at 3:44pm.
20ft*30ft*1in = 600ft^2-in
1 gal = 231 in^3
2.5gal = 577.5 in^3
1 ft^2-in = 144 in^3, so
2.5gal/min = 4.04 ft^2-in/min
or, .24935 min/ft^2 in
that's 149.61 min/600 ft^2-in
or, 2.4935 hr/600 ft^2-in
so, you will need roughly 2.5D hours to cover the area with D inches of water
since your formula is time(hr) = k*D(in), k must be in hr/in
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