A flux density of 1.2testa is produced in piece of castle by a magnetic force 1250a/m. Find the relative permability of the steel under these conditions.
B. Determine the magnetic flux strenght and magnetic force required to produce a flux density of 0.25testa in an air gap of lenght
12mm.
To find the relative permeability of the steel, we can use the formula:
μ_r = B / (μ_0 * H)
where:
μ_r is the relative permeability of the steel
B is the flux density (in teslas)
μ_0 is the permeability of free space (constant value of 4π x 10^-7 T*m/A)
H is the magnetic field strength (in amperes per meter)
Given:
B = 1.2 testa = 1.2 x 10^12 T
H = 1250 A/m
Plug these values into the formula:
μ_r = (1.2 x 10^12 T) / (4π x 10^-7 T*m/A * 1250 A/m)
Calculating this expression will give us the relative permeability of the steel.
Now, for the second question, we need to find the magnetic flux strength and the magnetic force required to produce a flux density of 0.25 testa in an air gap of length 12 mm.
To find the magnetic flux strength (Φ) in the air gap, we use the formula:
Φ = B * A
where:
Φ is the magnetic flux strength (in webers)
B is the flux density (in teslas)
A is the cross-sectional area of the air gap (in square meters)
To find the magnetic force (F) required, we use the formula:
F = B * μ_0 * H * l
where:
F is the magnetic force (in newtons)
B is the flux density (in teslas)
μ_0 is the permeability of free space (constant value of 4π x 10^-7 T*m/A)
H is the magnetic field strength (in amperes per meter)
l is the length of the air gap (in meters)
Given:
B = 0.25 testa = 0.25 x 10^12 T
l = 12 mm = 0.012 m (converted to meters)
Plug these values into the formulas to calculate the magnetic flux strength (Φ) and the magnetic force (F) required.