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Posted by on Saturday, March 31, 2012 at 11:23am.

A 200g tennis ball approaches a racket at 20m/s, is in contact with the racket for 0.008s, and the ball rebounds at 4m/s. Find the average force that the racket exerted on the ball.

  • physics - , Saturday, March 31, 2012 at 6:19pm

    Change of the linear momentum of the ball is
    Δp= mv1-(-mv2) =m(v1+v2) =0.2(20+4) =4.8 kg•m•s^-1
    Newton’s 2 Law
    F=Δp/Δt =4.8/0.008=600 N

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