Posted by **Nadine** on Saturday, March 31, 2012 at 9:32am.

Part of a single rectangular loop of wire with dimensions .35 m by .75 m (.35 is the height and .75 is the length) is situated inside a region of uniform magnetic field of 0.395 T. The total resistance of the loop is 0.690 Ω.

Calculate the force required to pull the loop from the field (to the right) at a constant velocity of 6.36 m/s. Neglect gravity.

- Physics -
**Elena**, Saturday, March 31, 2012 at 2:20pm
The induced emf in the loop is

ε =dΦ/dt =d(BwL)/dt=Bwv,

The current is

I = ε/R = Bwv/R

The force is

F =(Bw)^2v/R

(W =0.35 m, B = 0.395 T, v =6.36 m/s,

R= 0.690 Ω)

## Answer This Question

## Related Questions

- Physics - Part of a single rectangular loop of wire with dimensions .35 m by .75...
- physics - A rectangular wire loop of dimensions a×b, with a=3.5 cm and b=4.5 cm...
- magnetic field - A square loop with resistance R=0.001 Ohms,mass 1.0 gram, and ...
- Physics - Would someone check this please? A circular loop of wire of radius 0....
- Physics - Would someone check this please? A circular loop of wire of radius 0....
- Physics - Would someone check this please? A circular loop of wire of radius 0....
- physics - a rectangular loop with a=6.0 cm, and b=4.0 cm, moving with a velocity...
- physics - A rectangular loop with a=2.9 cm, and b=1.9 cm, moving with a velocity...
- Physics - A long, narrow rectangular loop of wire is moving toward the bottom of...
- Physics - A long, narrow rectangular loop of wire is moving toward the bottom of...

More Related Questions