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September 16, 2014

September 16, 2014

Posted by **Riya** on Saturday, March 31, 2012 at 12:53am.

This question exist of 4 parts I finished a and b, but still need c and d! Anyhow I am not getting the right answer someone please help.

(c) When the displacement is 2.55 cm from the equilibrium position, what is the speed of the brick?

(d) How long will it take for the brick to oscillate five times?

Thanks!

- physics -
**drwls**, Saturday, March 31, 2012 at 2:36amThe spring constant is

k = M*g/0.21 m = 51.3 N/m

(c) The sum of kinetic and (spring) potential energy is constant. The answer depends upon how much the spring was stretched before it was released and set in motion. You did not provide that information.

The oscillation period is

P = 2*pi*sqrt(M/k) = 0.92 seconds

It will take five tinmes that to osciallate five times, no matter how much it was initially stretched.

- physics to Drwls -
**Riya**, Saturday, March 31, 2012 at 11:09ama)(a) What is the spring constant of the spring?

51.3 N/m

(b) Luke now pulls the brick 5.1 cm from the equilibrium position to watch it oscillate. What is the maximum speed of the brick?

.35 m/s

So would you subtract 2.55 cm from 5.1 cm? To get how much was stretched?

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