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Four people sit in a car. The masses of the people are 41 kg, 47 kg, 53 kg, and 55 kg. The car's mass is 1020 kg. When the car drives over a bump, its springs cause an oscillation with a frequency of 1.00 Hz. What would the frequency be if only the 41-kg person were present?

I really don't know how to do this, and I can't even make an assumption! Help please!

  • Physics - ,

    M=41+47+53+55 = 196 kg
    f=sqrt(k/M)/ 2•π
    k =(2•π •f)^2•M =7.74•10^3 N/m
    f1 =sqrt(k/m)/ = sqrt(7.74•10^3/41)/ 2•π =2.19 Hz.

  • Physics to Elena - ,

    Thank you, but I tried this answer its wrong and I don't know why!

  • Physics - ,

    Thanks, for the help Elena. For me this answer is also not working its saying that its wrong. :/

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