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algebra

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z varies directly as x^2. If z=36 when x=3,find zwhen x=4.

  • algebra - ,

    z varies directly as x^2 -----> z = kx^2 , where k is a constant

    if z=36, x = 3
    336 = k(9)
    k = 4

    so y = 4x^2
    when x=4 , y = 4(16) = 64

    or , by ratio ....

    z1/z2 = x1^2/x2^2

    z1/36 = 4^2/3^2
    z1 = 36(16/9) = 64

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