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April 16, 2014

April 16, 2014

Posted by **sherry** on Friday, March 30, 2012 at 10:44pm.

- Intermediate Algebra -
**Steve**, Sunday, April 1, 2012 at 2:18pm(50x^2y^-4/200x^-2y^4)^3

First you can simplify inside the parens:

x^2/x^-2 = x^4

y^-4/y^4 = y^-8 = 1/y^8

50/200 = 1/4

so, now you are left with

(x^4/4y^8)^3 = x^12/64y^24

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