ALGEBRA
posted by XOCHIL on .
solve this system of equations and solve for triple pair:
x+y+z=8
2y+4y+2z=26
x+8y3z=26

I think your second equation is probably
2x+4y+2z=26
add the first and third > 9y  2z = 34 (#1)
multiply third by 2
2x + 16y  6z = 52
add that to the second
20y 4z = 78
10y  2z = 39 (#2)
#2  #1 : > y = 5
sub into #1
45  2z = 34
2z = 11
z = 5.5
back into the first
x + 5 + 5.5 = 8
x = 2.5
x = 2.5
y= 5
z = 5.5