Posted by Nadine on Friday, March 30, 2012 at 5:54pm.
The induced current will be in the dorection that increases the flux through the loop.
The magnitude of the induced emf is
d(Phi)/dt = B*dA/dt
= 0.78T*(pi/4)[(.178^2 -.064)^2]/0.22s
= 0.077 V
Divide by 2.9 ohms for the induced current.
Thank you!
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