Posted by **jof** on Friday, March 30, 2012 at 12:53pm.

The position of a car piston within the cylinder is described by the equation:

y = S sin(360

r t - 90

Where S is the stroke length of the cylinder, r is the rpm of the crank shaft, and t is

the time in minutes. If the stroke length is 2 inches and the crank shaft is running at

1300 rpm, find the position of the piston at t = 53 seconds. (remember that rpm

means revolutions per minute)

- Math -
**Steve**, Friday, March 30, 2012 at 2:15pm
what's the problem?

y(t) = S sin(360rt-90)

S = 2

r = 1300

t = 53/60

y(53/60) = 2sin(360*1300*53/60-90)

= 2sin(1148.3333*360 - 90)

now, we can toss out all multiples of 360, so we are left with

y = 2sin(240-90) = 2sin(150) = 2(.5) = 1.0

- Math - PS -
**Steve**, Friday, March 30, 2012 at 2:16pm
oops.

y = 2sin(120-90) = 2sin(30) = 2(.5) = 1.0

## Answer this Question

## Related Questions

- Physics - Suppose a monatomic ideal gas is contained within a vertical cylinder ...
- Physics - Suppose a monatomic ideal gas is contained within a vertical cylinder ...
- Physics - A 50 kg piston with a radius of 50 cm floats on a cylinder that is ...
- Physics HELP!!!!!!!! - Suppose a monatomic ideal gas is contained within a ...
- Physics - A car's brake system transfers pressure from the main cylinder to ...
- Chemistry - A sample consisting of 22.7 g of a nongaseous, unstable compound X ...
- ap chemistry - A sample consisting of 22.7 g of a nongaseous, unstable compound ...
- Physics HELP!!!!!!!! - Suppose a monatomic ideal gas is contained within a ...
- physics - A cylinder is fitted with a piston that is connected to the bottom by ...
- Physics - A hydraulic lift is used to jack a 780 kg car 15 cm off the floor. The...

More Related Questions