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February 1, 2015

February 1, 2015

Posted by **Jasmine** on Friday, March 30, 2012 at 12:37pm.

I took the derivative of the top and bottom and got 2x/(1/x) which is the same thing as 2x^2. Can I keep going or do I just say that the limit does not exist?

- Calculus -
**Steve**, Friday, March 30, 2012 at 2:01pmyou can keep going, but if you do, you're in trouble.

2x^2 = 2x^2/1

using the Rule, you'd have

4x/0 --> oo

So, the limit is as you found it, 2x^2 --> oo

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