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Posted by on Thursday, March 29, 2012 at 11:05pm.

Flying with the wind, a pilot flew 600 mi between two cities in 4 h. The return trip against the wind took 5 h. Find the rate of the plane in calm air and the rate of the wind. Please show work. thanks

  • algebra - , Friday, March 30, 2012 at 11:45am

    Distance (times) rate (times) time

    Let p represent the speed of the plane in still air

    Let w represent the speed of the wind

    600= (p+w)(4)
    600= (p-w)(5)

    600 divided by 4= 150= p+w
    600 divided by 5= 120= p-w

    150+120= 270=2p
    --- ---
    divide 2 2

    =135 =p

    p+w= 150
    135+w= 150
    -135 -135
    --------------
    w = 15

    The speed of the plane in still air is 135 mph.

    The speed of the wind is 15 mph.

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