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November 1, 2014

November 1, 2014

Posted by **Priscilla** on Thursday, March 29, 2012 at 10:33pm.

wavelength (lambda) = 400 nm

n1 = 2

RH = 2.18 x 10^-18

I keep having trouble with finding n2. Is the above given right to plug in for 1/(lambda) = RH (1/n1^2 - n2^2)

thank you for any help

- Chemistry -
**DrBob222**, Thursday, March 29, 2012 at 10:43pmno. Your constant is not right.

The Rydberg constant, R_{H}= 1.097E7.

1/wavelenth = RH(1/n1^2 - 1/n2^2)

wavelength must be converted to meters.

- Chemistry -
**Priscilla**, Thursday, March 29, 2012 at 10:46pmOkay, I was solving out this this equation for n2^2

n2^2 = 1(1/n - E/Rh)

Is this right?

- Chemistry -
**Priscilla**, Thursday, March 29, 2012 at 10:53pmIf its okay, can you show me in detail how to find n2^2 because I have done this three times and I'm still a little confused by this.

- Chemistry -
**DrBob222**, Thursday, March 29, 2012 at 10:56pmI think it is far easier to substitute the numbers, then do the math than try to manipulate all of the variables. I use one of the following where w = wavelength:

1/w = 2.180E-19/hc x (1/n1^2 - 1/n2^2) but it is much easier to simplify that by

1/w = R_{H}(1/n1^2 - 1/n2^2). That formula is the original Rydberg formula I believe. Using the 2.180 number as well as substituting h and c is just asking for more places for a mistake in my opinion.

- Chemistry -
**Priscilla**, Thursday, March 29, 2012 at 11:11pmok thank you very much

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