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December 18, 2014

December 18, 2014

Posted by **Casey** on Thursday, March 29, 2012 at 10:03pm.

please help, I am getting the wrong answer every time

- Calculus -
**Steve**, Friday, March 30, 2012 at 11:45amnot sure what you have there

ln(2^x)?

ln(2^x) = x*ln2

y' = ln2

y = log_{2}x ?

y = lnx/ln2

y' = 1/(x*ln2)

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