Post a New Question
posted by Casey Thursday, March 29, 2012 at 10:03pm.
derivative of y=ln2^x please help, I am getting the wrong answer every time
not sure what you have there ln(2^x)? ln(2^x) = x*ln2 y' = ln2 y = log_{2}x ? y = lnx/ln2 y' = 1/(x*ln2)
More Related Questions