Quadrilateral ABCD is a square. The coordinates of point A are (3,2), coordinates of point B are (-3,2),and the coordinates of points C are (-3,-4). where on a coordinate plane would I mark the location of point D??

In general, this takes some work, but in this case, just look at the points. It's very easy if you actually take the time to plot them on graph paper.

Note that (3,2) and (-3,2) are on the same horizontal line.

(-3,2) and (-3,-4) are on the same vertical line

(3,-4) is the missing point.

No you can't

I honsetly want the answers to this question

(3,2) ?

The missing point, D, must have the same vertical coordinate as A and the same horizontal coordinate as C because ABCD is a square.

Since A is at (3,2) and C is at (-3,-4), the horizontal coordinate of D is 3 - 6 = -3.

Since A is at (3,2) and C is at (-3,-4), the vertical coordinate of D is 2 - 6 = -4.

Therefore, the coordinates of D are (-3,-4).

Well, point D would be located at (drumroll please).... (3, -4)! That would complete our square and make it perfectly balanced, just like a square should be! So go ahead and mark point D there, and give your square a big round of applause for being so symmetrical!

To find the location of point D in the coordinate plane, we need to understand the properties of a square.

First, let's recall that in a square, opposite sides are parallel and equal in length. This means that side AB is parallel to side CD, and side AD is parallel to side BC. Since AB has a length of 6 units (3 units from A to the x-axis and 3 units from B to the x-axis), CD should also have a length of 6 units.

Next, we know that a square is symmetrical, which means that the midpoint of one side is the midpoint of the opposite side. The midpoint of AB can be found by taking the average of the x-coordinates and y-coordinates of A and B separately.

For the x-coordinate:
(3 + (-3))/2 = 0/2 = 0

For the y-coordinate:
(2 + 2)/2 = 4/2 = 2

So, the midpoint of AB is (0, 2). Since the midpoint of AB is also the midpoint of CD, the x-coordinate of D should also be 0.

Next, we can determine the y-coordinate of D. Since C has a y-coordinate of -4, and the length of CD is 6 units, the y-coordinate of D should be -4 + 6 = 2.

Therefore, the coordinates of point D are (0, 2).