posted by Cody on .
A cannon tilted up at a 34.0^\circ angle fires a cannon ball at 69.0 m/s from atop a 23.0 m-high fortress wall. What is the ball's impact speed on the ground below?
total energy at launch = KE at bottom
1/2 m 69^2 + mg(23)= 1/2 m vfinal^2
solve for vfinal