Posted by JJ on Thursday, March 29, 2012 at 9:13pm.
Find the derivative: y = square root of x(x+14).
The square root is only on the x. Please show work and explain. I don't know how to do this. Thanks!

Math  Steve, Friday, March 30, 2012 at 11:32am
if y = √u = u^(1/2)
y' = 1/2 * u^(1/2) u'
u = x^2+14x
u' = 2x+14
y' = (2x+14)/(2√x(x+14))
= (x+7)/√x(x+14)

Math  Oops  Steve, Friday, March 30, 2012 at 11:35am
oops. I didn't read it carefully
use the product rule: if
y = f*g, y' = f'*g + f*g'
y = (x+14)√x
y' = (1)√x + (x+14)*(1/2√x)
= (2x+x+14)/2√x
= (3x+14)/2√x
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