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April 23, 2014

April 23, 2014

Posted by **JJ** on Thursday, March 29, 2012 at 9:13pm.

The square root is only on the x. Please show work and explain. I don't know how to do this. Thanks!

- Math -
**Steve**, Friday, March 30, 2012 at 11:32amif y = √u = u^(1/2)

y' = 1/2 * u^(-1/2) u'

u = x^2+14x

u' = 2x+14

y' = (2x+14)/(2√x(x+14))

= (x+7)/√x(x+14)

- Math - Oops -
**Steve**, Friday, March 30, 2012 at 11:35amoops. I didn't read it carefully

use the product rule: if

y = f*g, y' = f'*g + f*g'

y = (x+14)√x

y' = (1)√x + (x+14)*(1/2√x)

= (2x+x+14)/2√x

= (3x+14)/2√x

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