Posted by jaeny on Thursday, March 29, 2012 at 7:58pm.
A coin of 5.30 gram is placed 12.0 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the turntable surface of = 0.900 and = 0.470.
What is the maximum angular velocity with which the turntable can spin without the coin sliding?

physics  drwls, Thursday, March 29, 2012 at 8:05pm
The static friction coefficient, Us, determines when it starts sliding.
M*g*Us = M*R*w^2
Solve for w, the angular velocity.
w = sqrt(g*Us/R) = 8.57 rad/s
Answer This Question
Related Questions
 Physics  A 5.0 g coin is placed 15 cm from the center of the turntable. THe ...
 Physics  A 6.80 g coin is placed 10.0 cm from the center of a turntable. The ...
 Physics  A 9.60 g coin is placed 10.7 cm from the center of a turntable. The ...
 Physics 1  A coin rests 12.0 cm from the center of a turntable. The coefficient...
 Physics HELP!  A coin rests 18.0 cm from the center of a turntable. The ...
 Physics URGENT!!!  A coin rests 18.0 cm from the center of a turntable. The ...
 Physics Elena please help!  A coin rests 18.0 cm from the center of a ...
 Physics Elena please help!  A coin rests 18.0 cm from the center of a ...
 physics  A coin rests 15.0 cm from the center of a turntable. The coefficient ...
 Physics  A coin rests 18.0 cm from the center of a turntable. The coefficient ...
More Related Questions