Posted by Sarah on Thursday, March 29, 2012 at 5:57pm.
The law of conservation of linear momentum for inelastic collision
m•v =(m +M) •u
v =(m +M) •u/m =(0.0124+1.02) •4.8/0.0124 = 399.6 m/s
KE1 =m•v^2/2 =0.0124•(399.6)^2/2 =990 J
KE2 = (m+M) •u^2/2=11.9 J
KE1 –KE2 =990 -11.9 = 978.1J
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