Posted by Michelle on Thursday, March 29, 2012 at 5:41pm.
A toss of two dice have 6*6=36 possible outcomes.
The 6 favourable outcomes with a sum of 7 are:
1+6,2+5,3+4,4+3,5+2 and 6+1.
P(7)=number of favourable outcomes / number of possible outcomes.
=6/36
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