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September 20, 2014

September 20, 2014

Posted by **Lavern** on Thursday, March 29, 2012 at 5:22pm.

(v-5)/(v-6)-(v+1)/(v+6)+(v-18)/(v^2-36)

- Math Problem -
**MathMate**, Thursday, March 29, 2012 at 6:25pmNotice that the denominator consists of

(v-6), (v+6), and (v^2-36)=(v+6)(v-6)

Therefore the common denominator is

(v²-36)=(v+6)(v-6)

The first fraction becomes:

(v-5)(v+6)

-------------

(v²-36)

The second fraction becomes:

(v+1)(v-6)

-------------

(v²-36)

And the third one stays at:

(v-18)

-------------

(v²-36)

Since we have a common denominator, we can expand the numberators and add to get:

7(v-6)

---------

(v+6)(v-6)

which after cancelling gives:

7/(v+6).

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