Posted by Maggie on .
Each of the four wheels of a car push on the road with a force of 4.0*10^3 N [down]. The driving force on the car is 8.0*10^3 N [W]. The fictional resistance on the car is 6.0*10^3 [E]. Calculate the following
A) the mass of the car
B) the net force on the car
C) the cars acceleration
The answers are
A) 1.6*10^3 kg
B) 2.0*10^3 N [W]
I just don't understand how to get these correct answers
M•g =4•m•g= 4•4•10^3 N
M = 4•4•10^3/9.8 =1.63•10^3 kg
There are 4 forces: Mg (downwards), normal force N ( upwards), driving force(to the left), and resistance force (to the right) . Net force is their sum.
Since N=Mg, net force is 8•10^3 – 6•10^3 = 2•10^3 N (to the left).
Acceleration = net force/mass =2•10^3/1.63•10^3 = 1.23 m/s^2