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March 25, 2017

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How many grams of lead(ii)iodide are generated when 400.0ml of 1.25M NaI reacts with 525.0ml of 1.00M Pb(NO3)2 according to the following balanced equeation?

2NaI + Pb(NO3)2---> 2NaNO3 + PbI2

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