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February 1, 2015

February 1, 2015

Posted by **Sur** on Thursday, March 29, 2012 at 10:59am.

- trig -
**Bosnian**, Thursday, March 29, 2012 at 11:59am2 sin ^ 2 ( x ) - 1 = 0

2 sin ^ 2 ( x ) = 1 Divide both sides by 2

sin ^ 2 ( x ) = 1 / 2

sin ( x ) = ± 1 / sqrt ( 2 )

sin ( x ) = 1 / sqrt ( 2 )

for

x = pi / 4 and x = 3 pi / 4

sin ( x ) = - 1 / sqrt ( 2 )

for

x = 5 pi / 4 and x = 7 pi / 4

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