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March 29, 2017

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2sin^2x-1=0[0,2pi)

  • trig - ,

    2 sin ^ 2 ( x ) - 1 = 0

    2 sin ^ 2 ( x ) = 1 Divide both sides by 2

    sin ^ 2 ( x ) = 1 / 2

    sin ( x ) = ± 1 / sqrt ( 2 )




    sin ( x ) = 1 / sqrt ( 2 )

    for

    x = pi / 4 and x = 3 pi / 4



    sin ( x ) = - 1 / sqrt ( 2 )

    for

    x = 5 pi / 4 and x = 7 pi / 4

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