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April 23, 2014

April 23, 2014

Posted by **Yoona** on Thursday, March 29, 2012 at 6:17am.

- calculus -
**naseba**, Thursday, March 29, 2012 at 9:09amare you sure this is a question?

- calculus -
**Steve**, Thursday, March 29, 2012 at 11:54amthis is just a standard acceleration problem.

s = 1/2 at^2

16 = 1/2 * 2 * t^2

16=t^2

t=4

so, in 4 min the house will be 16' tall, and he will be (briefly) safe.

- calculus -
**Steve**, Thursday, March 29, 2012 at 11:56amnow, if you want to use your calculus, let f(t) be the height of the house after t minutes.

f ''(t) = 2

f '(t) = 2t + c

f '(0) = 0 means c=0 and

f '(t) = 2t

f(t) = t^2+c

f(0) = 0 means c=0, so

f(t) = t^2

16 = t^2

t=4

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