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chem help

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the primary visible emissions from mercury are 404.7 nm and 435.8 nm. Calculate the frequencies for these emissions. Calculate the energy of a single photon and of a mole of photons of light with each of these wavelengths.

  • chem help - ,

    c = frequency*wavelength
    404.7 and 435.8 are wavelenths in nm. Convert those to m.
    E = hc/wavelength for one photon.
    That x 6.022E23 for a mole of photons.

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