Posted by Amber on Thursday, March 29, 2012 at 1:00am.
i really need help with this right now!!!!
The ppt is BaCO3
This is a limiting reagent problem. I know that because amounts are given for BOTH reactants.
Ba(OH)2 + CO2 ==> BaCO3 + H2O
1. Convert 95.65g Ba(OH)2 to mols. mols = grams/molar mass
2. Do the same for 88 g CO2.
3a. Using the coefficients in the balanced equation, convert mols Ba(OH)2 to mols BaCO3.
3b. Do the same for mols CO2.
3c. You will have two values for mols BaCO3 produced and only one can be correct. The correct value in limiting reagent problems is ALWAYS the smaller one and the reagent producing that number is the limiting reagent.
4. Using the smaller number, convert mols to g. g BaCO3 = mols x molar mass BaCO3.
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