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April 20, 2014

April 20, 2014

Posted by **kelly** on Wednesday, March 28, 2012 at 10:22pm.

- math -
**PsyDAG**, Thursday, March 29, 2012 at 8:16pmArea of circle = πr^2

Perimeter of a circle = 2πr

Diameter = 2r

Paint needed = (2πr^2 + 24[2πr])/50

I'll let you do the calculations.

- math -
**Samantha (Sam)**, Tuesday, May 1, 2012 at 6:38pm5 Cans

SA=2B+PH

SA=2(pi*r^2)+(2*pi*r)H

SA=2(3.14*3.4^2)+(2*3.14*3.4)8

SA=2*36.2984+21.352*8

SA=72.5968+170.816

SA=243.4128 ft^2

- Math -
**Samantha (Sam)**, Tuesday, May 1, 2012 at 6:38pm5 Cans

SA=2B+PH

SA=2(pi*r^2)+(2*pi*r)H

SA=2(3.14*3.4^2)+(2*3.14*3.4)8

SA=2*36.2984+21.352*8

SA=72.5968+170.816

SA=243.4128 ft^2

- math -
**Samantha (Sam)**, Tuesday, May 1, 2012 at 6:39pm5 Cans

SA=2B+PH

SA=2(pi*r^2)+(2*pi*r)H

SA=2(3.14*3.4^2)+(2*3.14*3.4)8

SA=2*36.2984+21.352*8

SA=72.5968+170.816

SA=243.4128 ft^2

CANS=243.4128/50=5 cans

- Math -
**Samantha (Sam)**, Tuesday, May 1, 2012 at 6:39pm5 Cans

SA=2B+PH

SA=2(pi*r^2)+(2*pi*r)H

SA=2(3.14*3.4^2)+(2*3.14*3.4)8

SA=2*36.2984+21.352*8

SA=72.5968+170.816

SA=243.4128 ft^2

CANS=243.4128/50=5 cans

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