Posted by Brynn on Wednesday, March 28, 2012 at 10:03pm.
This is too long and too detailed to post; in general what you do is start with mols HCl, add x mols NaOH, subtract mols to see mols HCl unreacted, then M = mols/L (remember this is total volume which is mL HCl to start plus mL NaOH added). Then pH = -log(H^+)
I can expand on individual questions if you get stuck one of them. Post your work.
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