Posted by bobby on Wednesday, March 28, 2012 at 9:16pm.
Let
f(x) = (7^(x))* (log base 3 of(x))
f '(x) =

math  Steve, Thursday, March 29, 2012 at 11:23am
you just need to memorize a couple more formulas:
you know that if
f = e^x
f' = e^x
f = a^x
f' = a^x ln(a)
log_{b}x = ln(x)/ln(b)
f = log_{b}x
f' = 1/ln(b) * 1/x
so, for f above,
f' = 7^x ln7 log_{3}x + 7^x * 1/xln3
= 7^x ln7 lnx/ln3 + 7^x *1/xln3
= 7^x/xln3 (x ln7 lnx + 1)
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