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March 3, 2015

March 3, 2015

Posted by **bobby** on Wednesday, March 28, 2012 at 9:16pm.

f(x) = (7^(x))* (log base 3 of(x))

f '(x) =

- math -
**Steve**, Thursday, March 29, 2012 at 11:23amyou just need to memorize a couple more formulas:

you know that if

f = e^x

f' = e^x

f = a^x

f' = a^x ln(a)

log_{b}x = ln(x)/ln(b)

f = log_{b}x

f' = 1/ln(b) * 1/x

so, for f above,

f' = 7^x ln7 log_{3}x + 7^x * 1/xln3

= 7^x ln7 lnx/ln3 + 7^x *1/xln3

= 7^x/xln3 (x ln7 lnx + 1)

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