Eighty grams of sodium nitrate dissolved in 50 grams of water will make what type of solution?

What temperature? At 20 C 41 g NaNO3 will dissolve in 100 mL H2O. At 20 C, then, this would be a saturated solution.

To determine the type of solution formed by dissolving sodium nitrate in water, we need to compare the amount of solute (sodium nitrate) to the amount of solvent (water) and examine the solubility of sodium nitrate.

The given mass of sodium nitrate is 80 grams, and the mass of water is 50 grams.

To calculate the solubility of sodium nitrate, we need to know the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature.

Let's assume that the solubility of sodium nitrate in water is 200 grams per 100 grams of water at the given temperature.

Now, we can solve for the solubility in the given ratio:

80 grams of sodium nitrate / 50 grams of water = (80 / 50) x (200 / 100)

Simplifying the equation:

1.6 x 2 = 3.2

So, in this case, we have a solution with a concentration of 3.2 grams of sodium nitrate per gram of water.

Since the concentration is greater than 1 (meaning that the solute is more concentrated than the solvent), this results in a saturated solution.