Posted by dmkp on Wednesday, March 28, 2012 at 12:51pm.
a) This is the inelastic collision.
b)
v =40 km/h=11.11 m/s
M(st)•0+M(mov) •v=(M(st)+M(mov)) •V
V= M(mov) •v/(M(st)+M(mov))=1300•11.11/(1300+1500) =5.158 m/s.
c) m•a =F(fr) = k•m•g
a=k•g =0.4•9.8 =3.92 m/s.
s=v^2/2a = (11.11)^2/2•3.92 = 15.72 m
0 = v- at
t = v/a – 11.11/3.92 = 2.83 s.
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