Posted by **Terry** on Wednesday, March 28, 2012 at 11:56am.

During the first part of a trip, a canoeist travels 69 miles at a certain speed. The canoeist traveled 23 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip is 2 hrs. What was the speed on each part of the trip?

- algebra -
**george**, Wednesday, March 28, 2012 at 4:29pm
1st part 69m @ X+5mph

2nd part 23m @ X

so,69m/x+5 + 23m/x = 2hours

69/x+5 + 23/x = 2

LCD ==> 69(x)+ 23(x+5)= 2x(x+5)

69x+23x+115=2x^2+10x

92x+115=2x^2+10x

0=2x^2-82x-115

wont factor, use quadratic formula

x=(-b}(b^2-4ac))/2a

x=-(-82)}(-82)^2 -(4)(2)(-115) / 2(2)

+82 = 39.55mph, -82 = negative number

so, 23 miles @ 39.55mph and 69 miles

@ (39.55 + 5mph =) 44.55mph

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