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April 20, 2014

April 20, 2014

Posted by **Alex** on Wednesday, March 28, 2012 at 8:05am.

(a) What is the average acceleration of the bullet as it passes through the board?

Give your answer in in scientific notation rounded to three significant figures.

(b) What is the total time that the bullet is in contact with the board?

Round your answer to the nearest millionth, if necessary. Give your answer in seconds.

**This I have correctly calculated to be 0.000390seconds***

(c) What thickness of board (calculated to 0.1 cm) would it take to stop the bullet, assuming the bullet's acceleration through all boards is the same?

Give your answer in centimetres.

- Physics -
**Elena**, Wednesday, March 28, 2012 at 10:45ama=(V^2-Vo^2)/2•s

s=11.5+1.85=13.35 cm=0.1335 m

a =2.95•10^5 m/s

t=(V-Vo)/a =0.000390 s

s1 = V^2/2•a = 0.542 m=54.2 cm

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