Tuesday
October 21, 2014

Homework Help: Chemistry

Posted by Ellen on Wednesday, March 28, 2012 at 5:30am.

The formaldehyde content of a pesticide preparation was determined by weighing 0.3124g of the liquid sample into a flask containing 50.0mL of 0.0996M NaOH and 50mL of 3% H2O2. Upon heating, the following reaction took place:

OH- + HCHO + H2O2 -> HCOO- + 2H2O

After cooling, the excess base was titrated with 23.3mL of 0.05250M H2SO4. Calculate the percentage of HCHO (30.026g/mol) in the sample.

Please explain throughly step by step on how to do this question. Thanks.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chem Quanti - An organic pesticide (MW 183.7) is 8.43% Cl. A 0.627-g sample ...
Science - A 5.0ml aliquot of a sample was transferred to a 25.0ml flask and ...
chemistry - HCl is titrated with NaOH. When doing the titration, some of the ...
chemistry - The purity of a pharmaceutical preparation of sulfanilamide, ...
AP Chemistry - The molar mass of a volatile liquid (one which vaporizes easily) ...
chemistry - The molar mass of a volatile liquid(one which vaporizes easily) can ...
chemistry - Hydrogen peroxide, H2O2, is used to disinfect contact lenses. What ...
Chemistry - a 20.0ml sample of HCL solution is placed in a flask with a few ...
chemistry - A chemist titrates 17.44 mL of 0.346 M NaOH into a flask containing ...
chemistry - A 5 mL sample of an unknown liquid is placed into a 250 mL flask ...

Search
Members