Posted by ALISON on Wednesday, March 28, 2012 at 2:54am.
250 mL x 0.250M = 62.5 millimols HAc
250 mL x 0.250M = 62.5 mmols NaAc.
add 5 mmols HAc
add 5 mmols NaOH
............Ac^- + H^+ ==> HAc
initial.....62.5..........62.5
add................5...........
change......-5....-5......+5
equil.....57.5.....0......67.5
Substitute into the Henderson-Hasselbalch equation and solve for pH.
The same process will work the NaOH part.
equil.....
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