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December 18, 2014

December 18, 2014

Posted by **mrsweetlaeh** on Tuesday, March 27, 2012 at 10:40pm.

thanks

- grade 11 math -
**Reiny**, Tuesday, March 27, 2012 at 11:19pmto break even, p(x) = 0

-.3x^2 + 3x - 15 = 0

times -10

3x^2 - 30x + 150=0

x^2 - 10x + 50 = 0

x = (10 ± √-100)/2

this has no real solution, the company will never make a profit.

- grade 11 math -
**mrsweetlaeh**, Tuesday, March 27, 2012 at 11:25pmWhere did the "times -10" come from?

- grade 11 math -
**MAT**, Sunday, April 1, 2012 at 8:48pmin order to break even he would have to produce

-o.3x^2+3x-15 factor use quadratic formula

you get two answers

5+the square root of 27

5-the square root of 27

because the second answer gives you a negative (you cant produce a negative amount of product) use the first one

10.19615242 is equivalent to x

so unless you can produce and sell .19615242 of a product which i don't know depending on the industry you just might be able, he cant break even.

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