Tuesday
March 28, 2017

Post a New Question

Posted by on .

You like to swim at a nearby lake. On one side of the lake is a cliff, and the top of the cliff is 36m above the surface of the lake. You dive off the cliff doing somersaults so as to have an angular speed of 6rev/min. How many revolutions do you make before you hit the water? Assume your initial centre of mass velocity is horizontal and you begin from a standing position. Do you enter the water head or feet first?

  • Physics - ,

    Time to fall H = 36 m =
    t = sqrt(2H/g) = 2.71 s
    Number of rotations on the way down =
    6.0 rev/min*(2.71/60)min = 0.27 rev

    The diver would land in a belly flop.

    6 rev/min is an extremely slow somersaulting rate. Are you sure that is the right number and dimension?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question