Posted by **Taylor** on Tuesday, March 27, 2012 at 5:08pm.

A 70-kg fisherman in a 138-kg boat throws a package of mass m = 15 kg horizontally toward the right with a speed of vi = 4.8 m/s as in the figure below. Neglecting water resistance, and assuming the boat is at rest before the package is thrown, find the velocity of the boat after the package is thrown.

magnitude m/s

direction

- physics -
**Girmaye**, Thursday, April 12, 2012 at 4:48pm
15*4.8+(70+138)v2=0

72+208v2=0

v2=2.88m/s to left

- physics -
**Nate**, Thursday, October 11, 2012 at 1:05am
This problem was done wrong. same equation but the answer was solved incorrectly. Your solving for v2. so 72 should be divided by the 208 not the other way around. The answer should be less the 1. around 0.346.

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