Posted by Roman on Tuesday, March 27, 2012 at 5:16am.
#1 and #5 will give you the order for NO which I see as 2.
#1 and #2 will give you the order for O2 which I see as 1 so the rate constant expression is
rate = k[NO][O2]2
The overall order is the sum of the individual orders.
Take any one experiment and substitute the number into the rate expression; solve for k.
thank you. I don't understand why the O2 is to the power of two in the rate = k[NO][O2]2 when that is only a first order reaction and the NO is second order.
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