Homework Help: algebra

Posted by Anonymous on Monday, March 26, 2012 at 11:31pm.

$6300 is invested,part of it at 10% and part of it at 7%.For a certain year, the total yield is $534.00. How much was invested at each rate

algebra - Reiny, Tuesday, March 27, 2012 at 7:39am
amount invested at 10% --- x
amount invested at 7% --- 6300-x

solve for x ....

.1x + .07(6300-x) = 534

I suggest multiplying each side by 100

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