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October 31, 2014

October 31, 2014

Posted by **Anonymous** on Monday, March 26, 2012 at 11:31pm.

- algebra -
**Reiny**, Tuesday, March 27, 2012 at 7:39amamount invested at 10% --- x

amount invested at 7% --- 6300-x

solve for x ....

.1x + .07(6300-x) = 534

I suggest multiplying each side by 100

- algebra -
**stacy**, Sunday, February 16, 2014 at 5:54pm$6300 is invested, part of it at 10% and part of it at 69%. For a certain year the total yield is $598.00. How much invested at each rate?

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