calculate the mass of kool aid required to prepare 200.0 ml of 0.30 M kool aid
Certainly, just as soon as you tell me the molar mass of kool aid.
How many mols kool aid do you need? That is M x L = ?
Then mol kool aid = grams kool aid/molar mass kool aid. Solve for grams.
To calculate the mass of Kool-Aid required to prepare a solution, you need to know the molar concentration of the Kool-Aid (given as 0.30 M) and the volume of the solution you want to prepare (given as 200.0 mL).
The molar concentration (M) of a solution is defined as the number of moles of solute (in this case, Kool-Aid) per liter of solution.
First, convert the given volume from milliliters (mL) to liters (L) by dividing by 1000:
200.0 mL ÷ 1000 = 0.2 L
Next, use the molar concentration formula to calculate the number of moles of Kool-Aid needed:
Molarity (M) = moles of solute / liters of solution
Rearranging the formula, we have:
moles of solute = Molarity (M) × liters of solution
moles of solute = 0.30 M × 0.2 L
moles of solute = 0.06 moles
Now, to calculate the mass of Kool-Aid, we need to multiply the moles of solute by its molar mass. The molar mass of Kool-Aid will depend on its chemical formula, which is not provided. However, for the purposes of this explanation, let's assume the molar mass of Kool-Aid is 200 g/mol.
mass of Kool-Aid = moles of solute × molar mass
mass of Kool-Aid = 0.06 mol × 200 g/mol
mass of Kool-Aid = 12 g
Therefore, to prepare 200.0 mL of 0.30 M Kool-Aid, you would need approximately 12 grams of Kool-Aid.