March 24, 2017

Post a New Question

Posted by on Monday, March 26, 2012 at 5:36pm.

Suppose that a police car on the highway is moving to the right at 26 m/s, while a speeder is coming up from almost directly behind at a speed of 37 m/s, both speeds being with respect to the ground. The police officer aims a radar gun at the speeder. Assume that the electromagnetic wave emitted by the radar gun has a frequency of 6.00 x 10^9 Hz. Find the the difference between the frequency of the wave that returns to the police car after reflecting from the speeder's car, and the original frequency emitted by the police car.

  • Physics help! - , Wednesday, March 28, 2012 at 8:41pm

    F = ((V+Vr) / (V+Vs))*Fs.
    F = ((343+37) / (343+26))*6*10^9 = 6.18*10^9 Hz.

    F - Fs = 6.18*10^9 - 6.00*10^9 = 1.79*10^8 Hz.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question