Physics
posted by Anne on .
A loud speaker of mass 24.0 kg is suspended a distance of h = 2.00 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of 3.50 m. What is the tension in each of the cables?

Each cable holds one half the weight.
verticalforceleft=verticalforceright=24g/2*cosTheta*tension
but CosTheta=2/3.5
solve for tension 
Thanks! I did get this far, but it didn't seem right!