Posted by emily on .
51.59 g of water at 82.6 oC is added to a calorimeter that contains 48.01 g of water at 40.9 oC. If the final temperature of the system is 59.4 oC, what is the calorimeter constant (Ccalorimeter) ? Use 4.184 J/goC for the heat capacity of water.
heat gained by cool water + heat lost by warm water + heat lost by calorimeter = 0
[mass cool water x specific heat x (Tfinal-Tinitial)] + [mass warm water x specific heat x (Tfinal-Tinitial)] + Ccal x (Tfinal-Tinitial) = 0
Substitute FIRST, then solve for Ccal.